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Quick question: Molar solubility
Started by betterfuture
Because the saturated cobalt (III) itself already has higher concentration of [OH-], mixing it with the saturated thallium(III), which has lower [OH-], is equivalent to diluting [OH-].
Actually, the mixing itself will also dilute [Co] and [Tl] so you cannot really say anything about TI unless volumes are given, but [Co] will absolutely not precipitate. And that strikes out B, D.
Edit: A and C are both possible.
I don't think whoever wrote that question understood the concept very well.
Actually, the mixing itself will also dilute [Co] and [Tl] so you cannot really say anything about TI unless volumes are given, but [Co] will absolutely not precipitate. And that strikes out B, D.
Edit: A and C are both possible.
I don't think whoever wrote that question understood the concept very well.
Last edited:
I just don't understand how we are supposed to figure out the answer. We aren't really given much to figure out anything. My guess would have been D because they both have very small Ksp values.
Does this mean Cobalt hydroxide will dissolve more than thallium hydroxide? And why does cobalt not precipitate?
Does this mean Cobalt hydroxide will dissolve more than thallium hydroxide? And why does cobalt not precipitate?
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