Quick Question

[starseeker]

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Is a logarithim chart or a periodic table given to you when taking the MCAT?

 

[McGillGrad]

That is funny because I cannot remember but I am almost sure that you are given a periodic table but definitely no log chart.

 

[OwnageMobile]

No log chart. PT yes.

 

[PBandJ]

no logarithm chart. but a wise professor once taught me to just memorize the following (note: this is for logarithms of base 10):

log(2) = 0.3
log(3) = 0.48

simplify your logarithmic expression down to some form with all logarithms of numbers less than 10. if you know log(2) and log(3), using properties of logs, you can approximate almost all other logs. a few examples are included below:

log(4) = log(2*2) = log(2) + log(2) = 2*0.3 = 0.6
log(6) = log(3*2) = log(3) + log(2) = 0.48 + 0.3 = 0.78
[ by this method, log(5) would be somewhere in-between those two...probably around 0.69]
log(8) = log(2*2*2) = log(2)+log(2)+log(2) = 0.9
[again, log(7) would be somewhere in-between log(6) and log(8), probably around 0.85]
log(9) = log(3^2) = 2*log(3) = 2*0.48 = 0.96

and you should probably know that log(10) = 1.


i hope that helps!

Is a logarithim chart or a periodic table given to you when taking the MCAT?

 

[starseeker]

no logarithm chart. but a wise professor once taught me to just memorize the following (note: this is for logarithms of base 10):

log(2) = 0.3
log(3) = 0.48

simplify your logarithmic expression down to some form with all logarithms of numbers less than 10. if you know log(2) and log(3), using properties of logs, you can approximate almost all other logs. a few examples are included below:

log(4) = log(2*2) = log(2) + log(2) = 2*0.3 = 0.6
log(6) = log(3*2) = log(3) + log(2) = 0.48 + 0.3 = 0.78
[ by this method, log(5) would be somewhere in-between those two...probably around 0.69]
log(8) = log(2*2*2) = log(2)+log(2)+log(2) = 0.9
[again, log(7) would be somewhere in-between log(6) and log(8), probably around 0.85]
log(9) = log(3^2) = 2*log(3) = 2*0.48 = 0.96

and you should probably know that log(10) = 1.


i hope that helps!

Oh my goodness scentiment that helped me so much. Thanks alot