Real Cell (Battery)

[MedPR]

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A battery has a measured potential difference of 6.0v if no circuit is connected to it. When it is connected to a 10ohm resistor, the current is 0.57 amps. What is the internal resistance?

I did it a different way than NOVA and got the same answer. I want to make sure it's not a coincidence.

V=I(R+Rinternal)

6=0.57(10+Rinternal)
0.3=0.57Rinternal
Rinternal=0.53

I rounded it when I was doing it, but when I saw NOVA's work was different I checked with the exact values.

Here is how NOVA did it.

Vext=IRext
Vext=(0.57)(10)
Vext=5.7V

Rint=Vint/I
=0.3V/0.57A
Rint0.53ohms

 

[MT Headed]

I did it a different way than NOVA and got the same answer. I want to make sure it's not a coincidence.

👍