ok so lemme get this straight, maybe.
dH = dU + d(pV) by definition
dH = dU + PdV at constant pressure with volume changing (this is the case in neither calorimeter)
dH = dU when you have constant pressure and the volume also does not change (if you are working with a coffee cup calorimeter with a liquid solution that doesn't evolve gas, this is representative, and my understanding is that's what the ccupcal is used for). here E=q+w, but in a closed system U=q+w and no mass is leaving here so that is valid. we've already said there's essentially no volume change here, so U=q since no pv work is done. so dH=dU and dU = q so dH=q. we directly measure heat by q=mcdT and that's how we get an enthalpy of reaction.
dH = dU + VdP when you have constant volume only (this is the bomb calorimeter). still no mass escaping, so E=U=q+w, and again no volume change means U=q. now we have dH= q + VdP. all of this looks measurable, so i take it that from here we find q via mcdT, measure V, Pinit, Pfinal, and directly calculate dH?
does all that jazz sound about right? thanks, my thermo people!