MedPR Membership Revoked Removed 10+ Year Member Joined Dec 1, 2011 Messages 18,577 Reaction score 57 Points 4,641 Pre-Podiatry Jan 12, 2012 #1 Advertisement - Members don't see this ad BR says v=lambda(frequency). Then it says the relationship between frequency and wavelength is not linear. Why/how is it not linear? Then it says that the relationship between speed and lambda is linear.
Advertisement - Members don't see this ad BR says v=lambda(frequency). Then it says the relationship between frequency and wavelength is not linear. Why/how is it not linear? Then it says that the relationship between speed and lambda is linear.
milski 1K member 10+ Year Member Joined Dec 30, 2009 Messages 2,640 Reaction score 527 Points 5,171 Location Where the rain grows Pre-Medical Jan 12, 2012 #2 frequency = v * 1/lambda Frequency is proportional to 1/lambda. It has to be proportional to lambda to be linear. Upvote 0 Downvote
frequency = v * 1/lambda Frequency is proportional to 1/lambda. It has to be proportional to lambda to be linear.
MedPR Membership Revoked Removed 10+ Year Member Joined Dec 1, 2011 Messages 18,577 Reaction score 57 Points 4,641 Pre-Podiatry Jan 12, 2012 #3 milski said: frequency = v * 1/lambda Frequency is proportional to 1/lambda. It has to be proportional to lambda to be linear. Click to expand... So indirectly proportional is not linear, but directly proportional is? I guess I thought everything was linearly related as long as there weren't any non-1 exponents involved. Upvote 0 Downvote
milski said: frequency = v * 1/lambda Frequency is proportional to 1/lambda. It has to be proportional to lambda to be linear. Click to expand... So indirectly proportional is not linear, but directly proportional is? I guess I thought everything was linearly related as long as there weren't any non-1 exponents involved.
milski 1K member 10+ Year Member Joined Dec 30, 2009 Messages 2,640 Reaction score 527 Points 5,171 Location Where the rain grows Pre-Medical Jan 12, 2012 #4 MedPR said: So indirectly proportional is not linear, but directly proportional is? I guess I thought everything was linearly related as long as there weren't any non-1 exponents involved. Click to expand... You are correct, the power has to be 1 but 1/lambda = lambda^(-1) and -1 is not the same as 1. For linearity you really need a=kb. Upvote 0 Downvote
MedPR said: So indirectly proportional is not linear, but directly proportional is? I guess I thought everything was linearly related as long as there weren't any non-1 exponents involved. Click to expand... You are correct, the power has to be 1 but 1/lambda = lambda^(-1) and -1 is not the same as 1. For linearity you really need a=kb.
MedPR Membership Revoked Removed 10+ Year Member Joined Dec 1, 2011 Messages 18,577 Reaction score 57 Points 4,641 Pre-Podiatry Jan 12, 2012 #5 milski said: You are correct, the power has to be 1 but 1/lambda = lambda^(-1) and -1 is not the same as 1. For linearity you really need a=kb. Click to expand... Ok thank you! Upvote 0 Downvote
milski said: You are correct, the power has to be 1 but 1/lambda = lambda^(-1) and -1 is not the same as 1. For linearity you really need a=kb. Click to expand... Ok thank you!