ph=-log[H+]
What mass of HCl is present in 0.250 L of a solution with a pH of 2.85?
2.85 = -log[H+]
Log is base 10, so you can see that the concentration of hydronium ions, as the above mentioned is the same as the liters of HCL, since HCL is a strong acid and will completely dissociate into CL- and H+...
Therefore,
[H+] = 10^(-2.85) ; this is the number of moles in one liter and you are given only 1/4 of a liter (0.250 L).
So, using D.A.: (10^(-2.85))*(.25) = 3.5x10^-4 moles of HCL * Molecular Weight of HCL = Answer.