justadream Full Member 10+ Year Member Joined Apr 29, 2011 Messages 2,171 Reaction score 863 Sep 15, 2014 #1 Do I have this backwards? V is velocity. T is temperature. V1/ V2= sqrt (T2/ T1) Members don't see this ad.
Do I have this backwards? V is velocity. T is temperature. V1/ V2= sqrt (T2/ T1) Members don't see this ad.
Cawolf PGY-2 10+ Year Member Joined Feb 27, 2013 Messages 3,469 Reaction score 2,287 Sep 15, 2014 #2 v = sqrt(3RT/m) v'/v = sqrt(3RT'/m)/sqrt(3RT/m) =sqrt(T')/sqrt(T) =sqrt(T'/T) I guess I don't see why you inverted the relationship. It makes sense that velocity goes up as temperature goes up and in the formula you posted, if T1 > T2, it will say that the temperature goes down. So I would think you need to flip the temps to be v'/v =sqrt(T'/T) Upvote 0 Downvote
v = sqrt(3RT/m) v'/v = sqrt(3RT'/m)/sqrt(3RT/m) =sqrt(T')/sqrt(T) =sqrt(T'/T) I guess I don't see why you inverted the relationship. It makes sense that velocity goes up as temperature goes up and in the formula you posted, if T1 > T2, it will say that the temperature goes down. So I would think you need to flip the temps to be v'/v =sqrt(T'/T)
MelloTangelo Full Member 10+ Year Member Joined Jun 17, 2013 Messages 152 Reaction score 66 Sep 15, 2014 #3 I think you got that equation mixed up with the one for mass: V1/V2 = sqrt (M2/M1). Mass and velocity are inversely proportional. Temperature and velocity are directly proportional. Upvote 0 Downvote
I think you got that equation mixed up with the one for mass: V1/V2 = sqrt (M2/M1). Mass and velocity are inversely proportional. Temperature and velocity are directly proportional.
Cawolf PGY-2 10+ Year Member Joined Feb 27, 2013 Messages 3,469 Reaction score 2,287 Sep 15, 2014 #4 Yes, and it can all be derived from the formula without memorizing each separate case. Upvote 0 Downvote