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If 7 clubs enter a ranking contest and there are four ranks to be awarded-1st,2nd, third and fourth. how many different arrangements of ranked clubs are there?
Order is important in this problem so we need to use: nPr = n!/[n-r]!
7P4 = 7!/[7-4]! = 7!/3! = 7x6x5x4x3x2x1/3x2x1 = 7x6x5x4 = 840
n!/[n-r]! or n!/r![n-r]!
the first equation is when order matters. the second equation is for figuring out combinations, when order doesn't matter.
If 7 clubs enter a ranking contest and there are four ranks to be awarded-1st,2nd, third and fourth. how many different arrangements of ranked clubs are there?
order matters here because say jack is 1st jim is second and jake is 3rd. Will it be the same thing is jake is 1st, jim is third and jack is second? No. Those will be totally different ranks.
So you can have more arrangements, order matters ===>Permutation
what are the key words to know if the order is important. I guess for this question since they say 1st, 2nd.....