fbradley99 Full Member 10+ Year Member Joined Jul 8, 2009 Messages 95 Reaction score 0 Jul 17, 2009 #1 I really do not understand how to mentally solve cube roots. For example 2.1 x 10-6=4x3 so you divide by 4..i understand that. But when it gets to cube I dont know how to do that by hand. .525 x 10^-6 =x3 so how do you figure out the cube root of .525 x 10-6 ???

I really do not understand how to mentally solve cube roots. For example 2.1 x 10-6=4x3 so you divide by 4..i understand that. But when it gets to cube I dont know how to do that by hand. .525 x 10^-6 =x3 so how do you figure out the cube root of .525 x 10-6 ???

matth87 Full Member Joined May 8, 2009 Messages 289 Reaction score 1 Jul 17, 2009 #2 fbradley99 said: I really do not understand how to mentally solve cube roots. For example 2.1 x 10-6=4x3 so you divide by 4..i understand that. But when it gets to cube I dont know how to do that by hand. .525 x 10^-6 =x3 so how do you figure out the cube root of .525 x 10-6 ??? Click to expand... First I would convert .525 x 10^-6 to 525 x 10^-9 Then the cubed root of 10^-9 = 10^-3, you just multiply by 1/3. Then I would try to find out which 3 numbers multiply together to get close to 525 7x7x7 = 343 8x8x8 = 512 So it has to be a little more then 8. so 8x10-3 Upvote 0 Downvote

fbradley99 said: I really do not understand how to mentally solve cube roots. For example 2.1 x 10-6=4x3 so you divide by 4..i understand that. But when it gets to cube I dont know how to do that by hand. .525 x 10^-6 =x3 so how do you figure out the cube root of .525 x 10-6 ??? Click to expand... First I would convert .525 x 10^-6 to 525 x 10^-9 Then the cubed root of 10^-9 = 10^-3, you just multiply by 1/3. Then I would try to find out which 3 numbers multiply together to get close to 525 7x7x7 = 343 8x8x8 = 512 So it has to be a little more then 8. so 8x10-3

fbradley99 Full Member 10+ Year Member Joined Jul 8, 2009 Messages 95 Reaction score 0 Jul 17, 2009 #3 very clever!!!! Upvote 0 Downvote

G G1SG2 Full Member 10+ Year Member 5+ Year Member Joined May 2, 2008 Messages 1,454 Reaction score 2 Jul 17, 2009 #4 matth87 said: First I would convert .525 x 10^-6 to 525 x 10^-9 Then the cubed root of 10^-9 = 10^-3, you just multiply by 1/3. Then I would try to find out which 3 numbers multiply together to get close to 525 7x7x7 = 343 8x8x8 = 512 So it has to be a little more then 8. so 8x10-3 Click to expand... Upvote 0 Downvote

matth87 said: First I would convert .525 x 10^-6 to 525 x 10^-9 Then the cubed root of 10^-9 = 10^-3, you just multiply by 1/3. Then I would try to find out which 3 numbers multiply together to get close to 525 7x7x7 = 343 8x8x8 = 512 So it has to be a little more then 8. so 8x10-3 Click to expand...

matth87 Full Member Joined May 8, 2009 Messages 289 Reaction score 1 Jul 17, 2009 #5 fbradley99 said: very clever!!!! Click to expand... Yeah approximations take a little bit of cleverness lol. Upvote 0 Downvote

fbradley99 said: very clever!!!! Click to expand... Yeah approximations take a little bit of cleverness lol.

hopslam Membership Revoked Removed 10+ Year Member Joined Apr 14, 2009 Messages 81 Reaction score 0 Jul 17, 2009 #6 stone cold Upvote 0 Downvote