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- Apr 24, 2013
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the equation is
2HCl + H2O2 + MnO2 --> O2 + MnCl2 + 2H2O
now, as far as I can tell,
Mn Is being reduced from +4 to +2. so it is the oxidizing agent
but what about O2?
O2 in H2O2 is -1 and it goes to being -2 in H2O.
but the answer says that O goes from -1 to 0 (from H2O2 to the O2).
Can anyone tell me why the answer ignores the oxidation state of O in H2O?
Thanks.
2HCl + H2O2 + MnO2 --> O2 + MnCl2 + 2H2O
now, as far as I can tell,
Mn Is being reduced from +4 to +2. so it is the oxidizing agent
but what about O2?
O2 in H2O2 is -1 and it goes to being -2 in H2O.
but the answer says that O goes from -1 to 0 (from H2O2 to the O2).
Can anyone tell me why the answer ignores the oxidation state of O in H2O?
Thanks.
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