- Joined
- Apr 20, 2008
- Messages
- 81
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got this from a friend that couldn't solve it...
Sec^2 (A) + Tan^2 (A-3) = 0
apparently the answer is (pi/4) but I'm not 100% sure of that cuz it don't make any sense!!! I've been lookin at this problem and trying to figure it out for a month now. still can't get it...
I just attempted it again and got stuck here:
1 = tan^2 (A-(Pi/60)) - tan^2 (A)
1 = tan (A) [tan (1-(Pi/60A)) - tan (Pi/180)]
I don't know if anything I'm doing is correct by the way. I'm not even sure if I can convert that "A-3" into radians from the beginning...
along with this problem, I have a piece of it that might be a step along the way?
2sin (A-1) = 0
Sec^2 (A) + Tan^2 (A-3) = 0
apparently the answer is (pi/4) but I'm not 100% sure of that cuz it don't make any sense!!! I've been lookin at this problem and trying to figure it out for a month now. still can't get it...
I just attempted it again and got stuck here:
1 = tan^2 (A-(Pi/60)) - tan^2 (A)
1 = tan (A) [tan (1-(Pi/60A)) - tan (Pi/180)]
I don't know if anything I'm doing is correct by the way. I'm not even sure if I can convert that "A-3" into radians from the beginning...
along with this problem, I have a piece of it that might be a step along the way?
2sin (A-1) = 0