Sec^2 (A) + Tan^2 (A-3) = 0

apparently the answer is (pi/4) but I'm not 100% sure of that cuz it don't make any sense!!! I've been lookin at this problem and trying to figure it out for a month now. still can't get it...

I just attempted it again and got stuck here:

1 = tan^2 (A-(Pi/60)) - tan^2 (A)

1 = tan (A) [tan (1-(Pi/60A)) - tan (Pi/180)]

I don't know if anything I'm doing is correct by the way. I'm not even sure if I can convert that "A-3" into radians from the beginning...

along with this problem, I have a piece of it that might be a step along the way?

2sin (A-1) = 0