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For those of you with TBR Chem.
So the answer says you have to write out the equilibrium expression and blah blah blah. Instead of doing that, couldn't you just use the part of the passage that says "The decrease in partial pressure of H2 gas is double the decrease in the internal pressure, based on the stoichiometry of reaction 1..." <-- in the last paragraph and below Figure 2.
If the decrease in partial pressure of H2 gas (4H2 in the reaction) is double the decrease in internal pressure, then doesn't that translate to the partial pressure of H2S (2H2S in the reaction) equalling the value of the change in pressure of the system and the partial pressure of CH4 (1CH4 in the reaction) equalling half the v alue for the change in pressure?
Isn't TBR's solution more work than necessary? Or is it coincidental that my method works?
So the answer says you have to write out the equilibrium expression and blah blah blah. Instead of doing that, couldn't you just use the part of the passage that says "The decrease in partial pressure of H2 gas is double the decrease in the internal pressure, based on the stoichiometry of reaction 1..." <-- in the last paragraph and below Figure 2.
If the decrease in partial pressure of H2 gas (4H2 in the reaction) is double the decrease in internal pressure, then doesn't that translate to the partial pressure of H2S (2H2S in the reaction) equalling the value of the change in pressure of the system and the partial pressure of CH4 (1CH4 in the reaction) equalling half the v alue for the change in pressure?
Isn't TBR's solution more work than necessary? Or is it coincidental that my method works?
