Tbr equlibrium passage 1

[crazy person]

---

Members do not see this ad.

Can someone please help me out with question #7 from passage 1 section III.

I'm not understanding why O2 is decreased since in the reaction there is only CaOH2 + CO2 -> CaCo3 + H2O. I get the whole adding and removing concentrations but for this problem, I'm not really getting what they are adding and removing in particular so it will shift to the right or to the left by increasing or decreasing the concentrations. I just don't see it.

 

[TopTomato]

Can someone please help me out with question #7 from passage 1 section III.

I'm not understanding why O2 is decreased since in the reaction there is only CaOH2 + CO2 -> CaCo3 + H2O. I get the whole adding and removing concentrations but for this problem, I'm not really getting what they are adding and removing in particular so it will shift to the right or to the left by increasing or decreasing the concentrations. I just don't see it.

Because you have to compare that the reaction 1 in the passage, in the rxn in the problem Ca(OH)2 reacts with CO2 to form CaCO3 and H2O. However the passage shows that CO2 is made by reacting 2 CO and O2. So when Ca(OH)2 is reacts with CO2 it removes it from reaction 1, which drives the reaction forward due to Le Chatlliers principle. Because reaction 1 is going forward O2 concentration will decrease.

 

[crazy person]

Because you have to compare that the reaction 1 in the passage, in the rxn in the problem Ca(OH)2 reacts with CO2 to form CaCO3 and H2O. However the passage shows that CO2 is made by reacting 2 CO and O2. So when Ca(OH)2 is reacts with CO2 it removes it from reaction 1, which drives the reaction forward due to Le Chatlliers principle. Because reaction 1 is going forward O2 concentration will decrease.

Oh I see now ! Thanks !