D discowisco Full Member 10+ Year Member Jun 26, 2013 #1 Advertisement - Members don't see this ad if the rate law for the following reaction is found to be rate = k (sqrt (Cl2)) x (HCCl3) what are the units for the rate law constant (k)?
Advertisement - Members don't see this ad if the rate law for the following reaction is found to be rate = k (sqrt (Cl2)) x (HCCl3) what are the units for the rate law constant (k)?
J Jepstein30 Full Member 10+ Year Member Jun 26, 2013 #2 discowisco said: if the rate law for the following reaction is found to be rate = k (sqrt (Cl2)) x (HCCl3) what are the units for the rate law constant (k)? Click to expand... Rate is always M/s. So if we have rate = k sqrt(Cl2) x HCCl3 M/s = k sqrt(M) * M M/(s*M*sqrt(M)) = k k = 1/(s*sqrt(M)) Upvote 0 Downvote
discowisco said: if the rate law for the following reaction is found to be rate = k (sqrt (Cl2)) x (HCCl3) what are the units for the rate law constant (k)? Click to expand... Rate is always M/s. So if we have rate = k sqrt(Cl2) x HCCl3 M/s = k sqrt(M) * M M/(s*M*sqrt(M)) = k k = 1/(s*sqrt(M))
C conquerDat Full Member 10+ Year Member Jun 26, 2013 #3 Thank you, was wondering why rate is = M/s but i reasoned that since Rate = k in 0 order and 0 order has the units M/s that thus rate would be M/s Thanks Upvote 0 Downvote
Thank you, was wondering why rate is = M/s but i reasoned that since Rate = k in 0 order and 0 order has the units M/s that thus rate would be M/s Thanks
J Jepstein30 Full Member 10+ Year Member Jun 26, 2013 #4 conquerDat said: Thank you, was wondering why rate is = M/s but i reasoned that since Rate = k in 0 order and 0 order has the units M/s that thus rate would be M/s Thanks Click to expand... That works. Also though, you're considering the rate of formation of a product.. so you want to figure out how much product (M) is produced per second (s) so M/s. Upvote 0 Downvote
conquerDat said: Thank you, was wondering why rate is = M/s but i reasoned that since Rate = k in 0 order and 0 order has the units M/s that thus rate would be M/s Thanks Click to expand... That works. Also though, you're considering the rate of formation of a product.. so you want to figure out how much product (M) is produced per second (s) so M/s.
