guys I am getting rocked with this tbr equilibrium passage because i dont get a simple math concept.
Compound 1: PCl3(g) + Cl2(g) <-->PCl5(g) Keq@ 100C= 1.95atm^-1
Compound 2: 2NO (g)+ Cl2(g) <--> 2 NOCl (g) Keq @ 100C= 2.1 *10^4 atm^-1
which compound is most readily oxidized by chlorine?
- The passage says that the greater the value of the equlib. const., the more favorable the rxn. I agree.
Then, the compound that is most readily oxidized will be the one that has the greater Keq? yes?
ok, now someone explain to me why compound 2 has a higher Keq than compound 1... I am getting messed up because of the atm^-1 term, i think..
Compound 1's Keq is basically 0.5 ---> 1/1.95
Compound 2's Keq will be 4.8e-5 ------> 1/2.1e4
HOW is compound 2 more favorable towards products???
EDIT: I know this seems like a dumb question because you can just see that both Keq's are the same units therefore you just need to look at the numbers but whats with the atm^-1??
Compound 1: PCl3(g) + Cl2(g) <-->PCl5(g) Keq@ 100C= 1.95atm^-1
Compound 2: 2NO (g)+ Cl2(g) <--> 2 NOCl (g) Keq @ 100C= 2.1 *10^4 atm^-1
which compound is most readily oxidized by chlorine?
- The passage says that the greater the value of the equlib. const., the more favorable the rxn. I agree.
Then, the compound that is most readily oxidized will be the one that has the greater Keq? yes?
ok, now someone explain to me why compound 2 has a higher Keq than compound 1... I am getting messed up because of the atm^-1 term, i think..
Compound 1's Keq is basically 0.5 ---> 1/1.95
Compound 2's Keq will be 4.8e-5 ------> 1/2.1e4
HOW is compound 2 more favorable towards products???
EDIT: I know this seems like a dumb question because you can just see that both Keq's are the same units therefore you just need to look at the numbers but whats with the atm^-1??
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