TBR O-Chem/Bio Discrepancy?

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coyotelime

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TBR O-Chem clearly said that anabolism = synthesis = reduction, examples include gluconeogenesis, fatty acid synthesis, and generally took place in the cytosol (Section 6, O-Chem book 2), and that catabolism = breaking down = oxidation, examples include glycolysis, generally took place in the matrix (except glycolysis).

But in a bio passage about insulin receptors, they ask what kind of wash should be used to break a disulfide bond(dimer). In the explanation, they say that breaking the S-S bond requires a reducing wash. Using their oxidation state definitions this makes sense. Either S in a S-S bond would have an oxidation state of 0(ignoring the other bonds' oxidation state contributions), and breaking that bond would add 1H each to the S, so the S-H would give S an oxidation state that is 1 less than before because S is more electronegative than H.

Am I missing something really basic here? Thanks.

Edit: Is there a difference between breaking down a molecule and breaking bonds? Also, as a general rule, I can just look at the oxidation state to make sure if it's oxidized/reduced correct?
 
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TBR O-Chem clearly said that anabolism = synthesis = reduction, examples include gluconeogenesis, fatty acid synthesis, and generally took place in the cytosol (Section 6, O-Chem book 2), and that catabolism = breaking down = oxidation, examples include glycolysis, generally took place in the matrix (except glycolysis).

I'm not sure if ALL anabolic reactions are reductive for the thing being built. Might be a generalization, might not. I can't think of an example of reductive catabolism or oxidative anabolism, but that doesn't mean it doesn't exist.

But in a bio passage about insulin receptors, they ask what kind of wash should be used to break a disulfide bond(dimer). In the explanation, they say that breaking the S-S bond requires a reducing wash. Using their oxidation state definitions this makes sense. Either S in a S-S bond would have an oxidation state of 0(ignoring the other bonds' oxidation state contributions), and breaking that bond would add 1H each to the S, so the S-H would give S an oxidation state that is 1 less than before because S is more electronegative than H.

When disulfide bonds break in a reducing solution, a hydrogen (or some reagent) is added to each sulfur, yup. Common example of this is adding beta-mercaptoethanol to your protein before you run it through an SDS-PAGE gel: cysteine-S--S-cysteine + 2 HOCH2CH2SH → 2 cysteine-SH + HOCH2CH2S-SCH2CH2OH

A bond is breaking, but bonds are forming too, so you can still think of that as reduction = bond formation, or, reduction = loss of oxygen or gain of hydrogen.

Edit: Is there a difference between breaking down a molecule and breaking bonds? Also, as a general rule, I can just look at the oxidation state to make sure if it's oxidized/reduced correct?

If a passage talks about breaking down a molecule, bonds are being broken, yeah. I can't think of anything else they'd be talking about. Change in oxidation state is one way to see if oxidation/reduction occurred. You can look for gain/loss of oxygen/hydrogen too, although that obviously doesn't work if those molecules aren't present. It does work for the reduction of disulfide bonds, as an example.
 
I'm not sure if ALL anabolic reactions are reductive for the thing being built. Might be a generalization, might not. I can't think of an example of reductive catabolism or oxidative anabolism, but that doesn't mean it doesn't exist.



When disulfide bonds break in a reducing solution, a hydrogen (or some reagent) is added to each sulfur, yup. Common example of this is adding beta-mercaptoethanol to your protein before you run it through an SDS-PAGE gel: cysteine-S--S-cysteine + 2 HOCH2CH2SH → 2 cysteine-SH + HOCH2CH2S-SCH2CH2OH

A bond is breaking, but bonds are forming too, so you can still think of that as reduction = bond formation, or, reduction = loss of oxygen or gain of hydrogen.



If a passage talks about breaking down a molecule, bonds are being broken, yeah. I can't think of anything else they'd be talking about. Change in oxidation state is one way to see if oxidation/reduction occurred. You can look for gain/loss of oxygen/hydrogen too, although that obviously doesn't work if those molecules aren't present. It does work for the reduction of disulfide bonds, as an example.

Okay. As a general rule I think I will just use oxidation states from now on to be safe. Thanks for your help!
 
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