Is R-NH3+ more acidic because it's the conj acid of a strong base (amine?). I think that's what confused me is I thought it was a basic group but I guess I answered my own question. Thanks.
R-NH2 and R-NH3+ are actually a conjugate pair where both are weak. R-NH2 has a pKb = about 4-5, and R-NH3+ has a corresponding pKa = 9-10
That's just a side note, I don't really have the greatest explanation for WHY R-NH3+ is more acidic than R-CF2OH, except that alcohols tend to be very weak acids, i.e., pKa > 14.
The fluorines, being more electronegative than oxygen, actually withdraw electron density from that -OH group, making it more acidic. That's the inductive effect, and might lead you to believe, "hey, here's an extra good alcohol, as far as acidity goes." The solution to 47 alludes to this a little, but you seem to be pretty clear on the -COOH vs. -CF2OH comparison, so no need to beat that point any more. I guess the lesson here is that the inductive effect of two fluorines isn't strong enough to boost the very weak alcohol into the pKa lower than 10 range, where it would beat the NH3+.
Whole other story here, sort of, but hydrogens bonded to carbons aren't usually acidic at all, except for special cases like alpha-carbonyl carbons, and those are still very weak (pKa = 19 or so) so flodhi1's post is a little confusing. If you compare an alkane and an alcohol, the alcohol, weak as it is, is way more acidic than random hydrogens in the alkane.