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A scientist operating a pendum in an elevator sees that the pendulum's period is shorter than can be accounted for by gravity alone if she takes measurements when the pendulum apparatus is moving with a constant:
A) Upward velocity
B) Downward velocity
C) Downward acceleration
D) Upward acceleration
A greater 'g' means a shorter period. To get a greater net gravitational force in the pendulum, T=2p*root(L/g), in addition to gravity, there should be constant acceleration that is in the SAME DIRECTION as g.
Here is where I do not understand:
In a free-body diagram, a downward acceleration would indicate: T-mg=m(-a) => g=(T+ma)/m. Wouldn't that mean an increase in acceleration to be an increase in g? So I got C.
Can anyone show me how you would do the freebody diagram so you get the correct answer D instead of C?
A) Upward velocity
B) Downward velocity
C) Downward acceleration
D) Upward acceleration
A greater 'g' means a shorter period. To get a greater net gravitational force in the pendulum, T=2p*root(L/g), in addition to gravity, there should be constant acceleration that is in the SAME DIRECTION as g.
Here is where I do not understand:
In a free-body diagram, a downward acceleration would indicate: T-mg=m(-a) => g=(T+ma)/m. Wouldn't that mean an increase in acceleration to be an increase in g? So I got C.
Can anyone show me how you would do the freebody diagram so you get the correct answer D instead of C?