TBR, Section 6, Passage 5, Question 28

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sillyjoe

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The question reads:

When using active radar, where radio waves are emitted from the same point at which the reflected waves are detected, all of the following should be considered EXCEPT:

A. the reflected wave is double Doppler-shifted by the moving object.
B. a stationary reference beam is needed.
C. the gun operates when stationary and in motion.
D. the best electromagnetic radiation is in the ultraviolet range.

Choice D is the best answer. When using active radar (such as a radar gun), the wave reflected from a moving object is in fact doubly compressed, which leads to a double Doppler shift. This makes choice A valid, so eliminate it. A reference beam is needed to compare how much the wave has shifted. This makes choice B valid, so eliminate it. The gun operates while stationary or in motion. But when in motion, the speed of the emitter must be factored in. If the speed is analyzed by comparing the wave reflected from a moving object with the wave reflected from a stationary object, then the motion of the gun subtracts out. This makes choice C valid, so eliminate it. The best electromagnetic radiation is one that can travel far and not be much affected by absorbance, refraction, or dispersion. The longer the EM wavelength, the better it is for use in radar.
This means that UV, with a short wavelength, would not work well. In addition, it would be expensive and dangerous to send out a signal of such high energy. For practical purposes, communication bands and radar are found at the low-energy/long- wavelength end of the electromagnetic spectrum. The best answer is D.

I was under the assumption that if the emitter is stationary it won't be "double Doppler-shifted". Can someone please explain why it is double shifted?
 
I was under the assumption that if the emitter is stationary it won't be "double Doppler-shifted". Can someone please explain why it is double shifted?
Because of the time variance. If it reaches the target 10% faster it will also return to the detector 10% faster, for a net 20% reduction in travel time at the same emission frequency.
 
Lot of possible radar scenarios that I feel would be hard to proof out but I believe for one dimension it seems to always be double. (Always is a hard word to stand behind,,, lol)

For 2 or 3 dimension calculations I believe the radar gun has to do internal trig calculations because it is not always double. I couldn't find any mathematical proofs of this but if you google "Moving Radar" there are some notable differences over 1 dimension calculations.

Conceptual examples Example:
http://www.rfcafe.com/references/electrical/ew-radar-handbook/doppler-shift.htm
http://www.rfcafe.com/references/electrical/doppler.htm

Images 1 and 2 show all the normal scenarios where the receiver and transmitter are moving directly toward or away from each other (elevation irrelevant)
Image 3 shows additional calculation required to determine radar shift based on objects not moving in the same direction.
img53.gif
img55.gif
img5A.gif
 
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