tbr test 3 bio number 112

[2010premed]

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How would you approach this problem, and what is the structure of dehudrated alumina?

Dehydrated alumina (Al2O3) has an activity rating of I. Hydrated alumina can have an activity rating between II and V, increasing with the percentage of bound water. From this, one can conclude that the activity rating of alumina increases numerically as
A. more solute is bound, because dehydrated alumina can readily accept lone-pair electrons from the solute.
B. more solute is bound, because dehydrated alumina cannot readily accept lone-pair electrons from the solute.
C. less solute is bound, because dehydrated alumina more readily accepts lone-pair electrons from the solute than hydrated alumina.
D. less solute is bound, because dehydrated alumina does not accept lone-pair electrons from the solute as readily as hydrated alumina.

 

[brood910]

Bump

 

[orangeblue]

I just took this test..let me review and write down what I gathered..

 

[orangeblue]

The correct answer is C right?

First thing to know is the Al when already bonded with h20 (hence hydrated vs. dehydrates ) doesnt' have electron pairs left over to interact with more solutes. So you are now down to A and C.

Clearly if Dehydrated Al is more active, then it's going to have more solute bound. and higher activity number (basically the I, II etc are just meaningless)--> hydrated--> less solute.