You have a strong base and a strong acid. so you would get a neutral product right?
But here the pH is 2 so that tells us we have added a bit more of the HCl to make the solution acidic.
so with a pH of 2 that means our [H+] concentration in the final solution is 0.01. (10^-2)
our total volume will be 20ml of naoh, 20 ml of HCl plus more of HCl which we'll call X.
why 20 of each? again strong acid + strong base = neutral so you need to have the same volume in order to neutralize it. So the final volume will be 40mL + X
Now we'll use the equation M1V1 = M2V2
M1 is out concentration of HCl
V1 is the volume of extra HCl needed
1M(x) = 0.01(40+x)
x = 4 + 0.01x
0.99x = 0.4
x = to about 0.4
so now we know that the extra amount of HCl added was 0.4 ml
But it wants the Total volume of HCl added.
so its 20 + 0.4 = 20.4 ml of HCl.
Hope this helps.
I'm wondering was 0.4 of of the answer choices?