Titration of H2SO4 with Ba(OH)2

[JSU]

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There was a passage on TBR test 7 that involved electrical conductivity and the titration of H2SO4 with Ba(OH)2. It said that the point of equivalence was at a pH of 7. However, should be final pH after the second equivalence point be greater than 7 because there is a conjugate base lying around? Im just trying to think through this. Maybe it doesnt work that way because all of the BaSO4 precipitates out?

 

[loveoforganic]

Yep! Barium sulfate is very, very insoluble. Barium ion is very poisonous, but doctors are able to use barium sulfate as a contrast medium in the veins because it's so insoluble it's safe.

 

[JSU]

Yep! Barium sulfate is very, very insoluble. Barium ion is very poisonous, but doctors are able to use barium sulfate as a contrast medium in the veins because it's so insoluble it's safe.

Sweet. So basically even though we are titrating a weak acid, there is no conj. base so the pH at equivalence will still be 7.

 

[loveoforganic]

Yep!

 

[JSU]

Nice...