A Aschematic Full Member 10+ Year Member Joined Oct 10, 2009 Messages 29 Reaction score 0 Points 0 Pre-Dental Nov 1, 2009 #1 Advertisement - Members don't see this ad Sorry. This may be an obvious question but I am wondering where that "4" in choice (a) came from. 😀 Thanks. (The correct choice is A.)
Advertisement - Members don't see this ad Sorry. This may be an obvious question but I am wondering where that "4" in choice (a) came from. 😀 Thanks. (The correct choice is A.)
Evergrey Full Member 10+ Year Member Joined Dec 27, 2008 Messages 1,471 Reaction score 8 Points 4,621 Medical Student Nov 1, 2009 #2 The wikipedia page on solubility equilibrium has that problem almost verbatim under "ionic compounds". Basically you use the Ksp value to convert to molar solubility, solve for x, and x is how much of the component is dissolved. Upvote 0 Downvote
The wikipedia page on solubility equilibrium has that problem almost verbatim under "ionic compounds". Basically you use the Ksp value to convert to molar solubility, solve for x, and x is how much of the component is dissolved.
W wantVCUdental Full Member 10+ Year Member Joined Aug 6, 2009 Messages 982 Reaction score 1 Points 4,531 Pre-Dental Nov 1, 2009 #3 Aschematic said: Sorry. This may be an obvious question but I am wondering where that "4" in choice (a) came from. 😀 Thanks. (The correct choice is A.) Click to expand... Cmon, a canadian student shouldn't be asking trivial questions like these 😀. BaF2-> Ba +2F x 2x Ksp=x(2x)^2 Ksp=4x^3 That's where the 4 came from 😀 good luck Upvote 0 Downvote
Aschematic said: Sorry. This may be an obvious question but I am wondering where that "4" in choice (a) came from. 😀 Thanks. (The correct choice is A.) Click to expand... Cmon, a canadian student shouldn't be asking trivial questions like these 😀. BaF2-> Ba +2F x 2x Ksp=x(2x)^2 Ksp=4x^3 That's where the 4 came from 😀 good luck
A Aschematic Full Member 10+ Year Member Joined Oct 10, 2009 Messages 29 Reaction score 0 Points 0 Pre-Dental Nov 1, 2009 #4 Thanks. Totally forgot about the "2" as coefficient. Upvote 0 Downvote