Topscore Gchem question

[whawha]

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delta H = -527 kJ

Answer says the reaction will be shifted to left when temperature goes up. I totally agree if there was an equilibrium arrow between reactants and products in the picture attached. It would indeed be shifted to left since it is an exthermic reaction (negative sign)

I picked "increasing temperature wouldn't do anything" because I thought the reaction was an irreversible one.

So, there should a both-way arrow in the problem, right?

 

[vlct0ria]

delta H = -527 kJ

Answer says the reaction will be shifted to left when temperature goes up. I totally agree if there was an equilibrium arrow between reactants and products in the picture attached. It would indeed be shifted to left since it is an exthermic reaction (negative sign)

I picked "increasing temperature wouldn't do anything" because I thought the reaction was an irreversible one.

So, there should a both-way arrow in the problem, right?

Yeah so it sounds they are wanting you to assume its at equilibrium and to use Le Chatelier's (which you did)...it should be a double sided arrow

 

[Valigator00]

delta H = -527 kJ

Answer says the reaction will be shifted to left when temperature goes up. I totally agree if there was an equilibrium arrow between reactants and products in the picture attached. It would indeed be shifted to left since it is an exthermic reaction (negative sign)

I picked "increasing temperature wouldn't do anything" because I thought the reaction was an irreversible one.

So, there should a both-way arrow in the problem, right?

This is a solubility reaction. Whenever solubility reaction exists, there is an equlibrium point. (Remember Qs, and Ksp?) In other words, solubility reactions can go in both ways. Since heat is on the right side of equation, rise in temperature would shift reaction to the left. I understand that they should have added two half errors. I do not know why they did not do that. 😀

 

[whawha]

Yeah so it sounds they are wanting you to assume its at equilibrium and to use Le Chatelier's (which you did)...it should be a double sided arrow

Thank you! 🙂))

 

[whawha]

This is a solubility reaction. Whenever solubility reaction exists, there is an equlibrium point. (Remember Qs, and Ksp?) In other words, solubility reactions can go in both ways. Since heat is on the right side of equation, rise in temperature would shift reaction to the left. I understand that they should have added two half errors. I do not know why they did not do that. 😀

Yes! that was my initial thought. But as I was looking at the arrow, I was like, this may be one of those crazy exceptions!!?!?? So, I picked that wrong answer... yes, I think there must be a both-sided arrow.