Exam 1 question 3 (73) says that there are 2 singlets in answer b. Can anyone please explain. The answer is not helping me.
Thanks
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yes post it don worry...No one here is gonna snitch on you...

Wouldn't acetone give 2 singlets as well? Or is it because there's symmetry, so only one H singlet is shown since they overlap? And 1,4 dimethoxybenzene shows two singlets because one from the aromatic H and one from the methoxy H? The other methoxy H and aromatic H's are equivalent so would just overlap, leading to only two visible singlets? Am I correct?![]()
thank you thank you!Yup, acetone should give only one singlet I think. All 6 H's are equivalent.
I think your reasoning is correct for 1,4-dmb as well.
