- Joined
- Apr 16, 2003
- Messages
- 31
- Reaction score
- 0
Could someone give me an explaination for this topscore problem please?
When 14.25 moles of PCl5 gas is placed in a 3.00 L container and comes to equillibrium at constant temperature, 40% of PCl5 decomposes according to this equation:
PCl5 (g)-------->PCl3 (g) +Cl2 (g)
What is the value of Kc of this reaction?
The answer is (1.896) squared/(2.854)
When 14.25 moles of PCl5 gas is placed in a 3.00 L container and comes to equillibrium at constant temperature, 40% of PCl5 decomposes according to this equation:
PCl5 (g)-------->PCl3 (g) +Cl2 (g)
What is the value of Kc of this reaction?
The answer is (1.896) squared/(2.854)