futuredentista

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May 3, 2006
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I thought that intermediates can't be included in the rate law expression. Would O not be considered an intermediate since the first step is reversible and thus, be allowed in the rate law?
 
Aug 3, 2009
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You might be thinking about intermediates not being allowed in the OVERALL reaction. The key to this problem is that it tells you which step is the slow (and therefore, rate-determining) step. Once you know the rate-determining step, finding the rate law is easy- simply raise each reactant to its respective coefficient ("1" in this case) and place a constant in front. This is a tricky one, but just know that the fact that the 2nd reaction step is slow is the KEY to this problem. Hope that helps