Translation Motion Eq. Derivation

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soccatrini08

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How is the following translational motion equation derived?


vx2 = vo2 + 2axΔx

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For anyone who has read the question but has not figured out how:

Δx= V0.t+at^2/2 and V=V0+at

From the second equation, t=(V-V0)/a, plug that instead of t in the first one, simplify and you'll get the formula above.
 
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