S soccatrini08 New Member 10+ Year Member Joined Mar 7, 2012 Messages 9 Reaction score 0 Points 0 Pre-Medical Jul 6, 2012 #1 Advertisement - Members don't see this ad How is the following translational motion equation derived? vx2 = vo2 + 2axΔx Last edited: Jul 6, 2012
Advertisement - Members don't see this ad How is the following translational motion equation derived? vx2 = vo2 + 2axΔx
S soccatrini08 New Member 10+ Year Member Joined Mar 7, 2012 Messages 9 Reaction score 0 Points 0 Pre-Medical Jul 6, 2012 #2 Never mind I figured it out. Upvote 0 Downvote
milski 1K member 10+ Year Member Joined Dec 30, 2009 Messages 2,640 Reaction score 527 Points 5,171 Location Where the rain grows Pre-Medical Jul 6, 2012 #3 For anyone who has read the question but has not figured out how: Δx= V0.t+at^2/2 and V=V0+at From the second equation, t=(V-V0)/a, plug that instead of t in the first one, simplify and you'll get the formula above. Upvote 0 Downvote
For anyone who has read the question but has not figured out how: Δx= V0.t+at^2/2 and V=V0+at From the second equation, t=(V-V0)/a, plug that instead of t in the first one, simplify and you'll get the formula above.