S soccatrini08 New Member 10+ Year Member Joined Mar 7, 2012 Messages 9 Reaction score 0 Jul 6, 2012 #1 How is the following translational motion equation derived? vx2 = vo2 + 2axΔx Members don't see this ad. Last edited: Jul 6, 2012
How is the following translational motion equation derived? vx2 = vo2 + 2axΔx Members don't see this ad.
S soccatrini08 New Member 10+ Year Member Joined Mar 7, 2012 Messages 9 Reaction score 0 Jul 6, 2012 #2 Never mind I figured it out. Upvote 0 Downvote
milski 1K member 10+ Year Member Joined Dec 30, 2009 Messages 2,641 Reaction score 527 Jul 6, 2012 #3 For anyone who has read the question but has not figured out how: Δx= V0.t+at^2/2 and V=V0+at From the second equation, t=(V-V0)/a, plug that instead of t in the first one, simplify and you'll get the formula above. Upvote 0 Downvote
For anyone who has read the question but has not figured out how: Δx= V0.t+at^2/2 and V=V0+at From the second equation, t=(V-V0)/a, plug that instead of t in the first one, simplify and you'll get the formula above.