Trig Question

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

vcuchic

Full Member
10+ Year Member
15+ Year Member
Joined
May 2, 2007
Messages
55
Reaction score
0
Hey Guys,

This is a math question straight out of TopScore...
I do not know how to approach this question, so any help would be greatly appreciated! Thank you!
I don't know how to put in symbols, so I apologize if the question is a little unclear. I tried my best 😳

Question:
4csc(theta) - 1 = 0
for all values where x is greater than or equal to 0
and
all values where x is less than 360.

Answer:
{empty}


Thank you!

 
I'm not entirely sure, but this is what I believe the explanation probably is:

4csc(theta) - 1 = 0
4csc(theta) = 1
csc (theta) = 1/4
By definition, csc theta = hypotenuse/opposite
thus, 1 = hyp, 4 = side opposite to the angle
but, according to the right angled triangle rules (I don't exactly remember the name of the rule/theorem #, but it states that), in a right angled triangle, the hyp is always greater than one of the sides of the triangle.

you could prove it mathematically using the pythagorean formula and plugging in #s.

I hope this helped.
 
Do a search cause I've answered this 5 times easily 😛

The problem is actually csc^2(theta).

4csc^2(theta) - 1 = 0
4csc^2(theta) = 1
csc^2(theta) = 1/4
csc(theta) = 1/2

1/sin(theta) = 1/2

sin(theta) = 2

This never happens.

If it is a different problem and it is just csc(theta) then you have sin(theta) = 4 which still never happens.
 
Top