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On AAMC MCAT Practice Test 5R #31, which asks about the concentration on the polymer. How does it find the answer to be (1/n)[HPO42-]. This one I have no idea.
ON AAMC MCAT Practice Test 7 Prob #24. I thought this was an easy one, but I guess I need some clarification. Since the Cu 2+ is getting reduced to Cu(s) that means it's the cathode, and since Oxygen is getting oxidized, it's the anode. So I plugged the electrode potentials in = E(cell) = E(cath) - E(anode) = .34 - -1.23 = 1.57V which is wrong.
The answer says you just add the two potentials. I know there's the equation E(cell) = E(red) + E(oxydation), but I thought this was the same as the equation above. Anyway, if someone could point out the flaw in my thought process, it'd be appreciated
ON AAMC MCAT Practice Test 7 Prob #24. I thought this was an easy one, but I guess I need some clarification. Since the Cu 2+ is getting reduced to Cu(s) that means it's the cathode, and since Oxygen is getting oxidized, it's the anode. So I plugged the electrode potentials in = E(cell) = E(cath) - E(anode) = .34 - -1.23 = 1.57V which is wrong.
The answer says you just add the two potentials. I know there's the equation E(cell) = E(red) + E(oxydation), but I thought this was the same as the equation above. Anyway, if someone could point out the flaw in my thought process, it'd be appreciated