growingpains

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Given the reaction:

2 NO2 (g) <--> N2O4 (g)

Kp = .2 atm^-1

and you start with .2 atm N2O4,

As of now, all I can deduce from the Kp is that the reverse reaction is favored, but how do you know, more specifically, that more than half of the .2 atm N2O4 will shift over?
 

pfaction

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This is from TBR. I know it. Just remember this: Kp is less than 1, which indicates more reactants than products. So it was going to be above 200, and less than 400. I hated that section.
 

growingpains

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Dec 22, 2011
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This is from TBR. I know it. Just remember this: Kp is less than 1, which indicates more reactants than products. So it was going to be above 200, and less than 400. I hated that section.

Yup, it's from BR and I'm also hating the section already. I get why it has to be less than 400, but I still don't get why it'd have to be greater than 200...
 
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