volume calculation problem

[Smooth Operater]

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the temp. of a closed container of a gas containing 1.00*10^2 ml is changed from 10 celsius to 20 celsisu. If the pressure is kept constant, the new volume of the gas wouuld be?

A. 50 ml
B. 100 ml
c. 103 ml
d. 200 ml
e. none of above

I said 200 ml since the temperature is doubled, and thus volume is doubled. But the correct answer according to my book is 103 ml. Who is right here? Thanks!

 

[joonkimdds]

the temp. of a closed container of a gas containing 1.00*10^2 ml is changed from 10 celsius to 20 celsisu. If the pressure is kept constant, the new volume of the gas wouuld be?

A. 50 ml
B. 100 ml
c. 103 ml
d. 200 ml
e. none of above

I said 200 ml since the temperature is doubled, and thus volume is doubled. But the correct answer according to my book is 103 ml. Who is right here? Thanks!

I think u r right.
whoever made this problem ....is a funny guy to put values of 100 and 103 where did u get this problem?

 

[jwilson02]

You are wrong im sorry to say. Lets take the Ideal gas equation PV=nRT
Set V to .1L or 100ml. Set R to 8(close enough) and T to 283K or 273 +10
Now we get P(.1)=n8(283) now we can set P to any pressure because it does not change, so make it 1 for simplicity

so 1(.1)=8n(283) or n=4.43e-5 mol

now our new temp is 293K or 273 +20
plug in our old P as 1 and V is what we want to find so make V=x
now 1(x)=4.43e-5(8)(293)
x=.1035 or about .103 L or 103 mL

volume is proportional to temperature only meaning that an increase in temperature leads to an increase in volume..but how much? that depends

a much simpler derivation is to take Charles law : V1/T1= V2/T2 Here we see that .1/273=x/283 cross multiply and get 28.3/273=x or aout .104 or 104 ml