What is always true at equilibrium

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Lunasly

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I understand that at equilibrium the delta G standard is 0, while delta G is not. However, what about the equilibrium constant. I understand that at equilibrium, the Keq = Q (reaction quotient), however, why doesn't it not equal 1?

Is it because you don't need an equal concentration of reactants or products to be at equilibrium? It's only in that scenario where you do have equal concentrations of reactants and products at equilibrium is Keq = 1?

Thanks.

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I understand that at equilibrium the delta G standard is 0, while delta G is not. However, what about the equilibrium constant. I understand that at equilibrium, the Keq = Q (reaction quotient), however, why doesn't it not equal 1?

Is it because you don't need an equal concentration of reactants or products to be at equilibrium? It's only in that scenario where you do have equal concentrations of reactants and products at equilibrium is Keq = 1?

Thanks.
First bold part:
Yes. I mean take complete dissociation of a compound. There is no reactant left, but equilibrium is achieved.
Second bold part:
No necessarily, depends on stoichiometric setup of the reaction. Doesn't have to be equal. Sure for trivial reactions with 1 compound on each side it is true, just compute it and see what it is.
 
First bold part:
Yes. I mean take complete dissociation of a compound. There is no reactant left, but equilibrium is achieved.

This is true, but only if there is solid compound still present, if you completely dissociate a compound in an aqueous solution it is not at equilibrium. I completely agree with the rest of your response i just wanted to make sure to point out that one thing.
 
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