When a capacitor is fully charged, RC Circuit Voltage=2V?

[hellocubed]

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I'm quite confused about this point.

BR gives this formula on page 186 of their physics book:

V= (V of resistors)+ (V of capacitor)
V=IR+(q/C)

And considering, in this case, V=IR=emf
and (q/C)=V=emf when the capacitor is fully charged.


So when the capacitor is fully charged:

V=emf+emf=2emf


Seems strange, but wondering if this was correct.

 

[hellocubed]

Oh wow, nevermind


When capacitor is fully charged,

V=IR+(q/C)

IR=0 because there is no more current through the circuit. so V=(q/C)