Which is more stable?

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rippinitez

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Here's an image from the free sample test provided by the ADA.

According to the answer key, B is more stable. But I don't see how it is different than A, both have one Br in the axial and one in the equatorial. . . Any ideas?
 

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Here's an image from the free sample test provided by the ADA.

According to the answer key, B is more stable. But I don't see how it is different than A, both have one Br in the axial and one in the equatorial. . . Any ideas?

Look more carefully. Are you sure both the bromines on A aren't axial?
 
I agree. It's bad..bad pic.

If students are spending great deal of time preparing for DAT..avg any where from 1 month to 4 months... multiply it with by number of people taking DAT...why can't people preparing questions spend just a lil more of their time and at least make it close to perfect for the people who is answering those question. I mean error in ADA sample test answer key !!! come one..that is ridiculous !!! I just took the Top score 2 ..found one answer wrong in key. I mean how hard is to proof-read !!!

Shouldn't we at least deserve fair material to prepare for DAT?

It took me ~5 min to type this. So far people have posted so many thread just to clarify the wrong answers..add those up..great deal of human time !!!
 
It seemed clear to me. SP3 = 109.5 degrees - not 90.

It's good thing that it seems clear to you.

But I got to say, you must have different way to look at the chair conformation. I thought chair confirmation is all about equatorial and axial presentation of cyclic compound and their substituents. I agree, SP3=109.5 but we are not making accurate 3D model of the compound in a space. It's chair representation of the cyclic compound. Two different things. One goes on paper and other suspended in space. 😀
 
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