B blinktonheim Full Member 10+ Year Member Feb 22, 2010 #1 Advertisement - Members don't see this ad NaOCH3 2-iodo butane --------> CH3OH answer in the book says E2.. am i missing something, wouldnt that polar protic solvent make it E1??
Advertisement - Members don't see this ad NaOCH3 2-iodo butane --------> CH3OH answer in the book says E2.. am i missing something, wouldnt that polar protic solvent make it E1??
B blinktonheim Full Member 10+ Year Member Feb 22, 2010 #2 the reaction is : 2-iodobutane reacted with NaOCH3 and CH3OH yields-----> Upvote 0 Downvote
D DATlongshui Full Member 10+ Year Member Feb 22, 2010 #3 It is E2, as CH3ONa is a strong base as well as a good nucleophile. For E1, it is weak base/weak nucleophile, such as CH3OH (alcohol). Upvote 0 Downvote
It is E2, as CH3ONa is a strong base as well as a good nucleophile. For E1, it is weak base/weak nucleophile, such as CH3OH (alcohol).
B blinktonheim Full Member 10+ Year Member Feb 22, 2010 #4 ok.. I see that.. but at the same time a polar solvent favors E1? thanks for your reply Upvote 0 Downvote
