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Started by prsndwg
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What about this one?
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I thought it was two singlets and 2 doublets.. but i guess not😕
I think The answer should be E-two singlets. since this compound has symmetry, all the carbons in the ring will be considered as one while being next to the carbon which has no hydrogens on it-the one with the methyl, which would give a singlet. Also, the methyl itself would be the other singlet since it is adjacent to the same carbon mentioned above.
I hope thats correct
For the acid problem what I gathered was when you're giving x% acid it's referring to the mass fraction not volume fraction of the acid in water.
I think The answer should be E-two singlets. since this compound has symmetry, all the carbons in the ring will be considered as one while being next to the carbon which has no hydrogens on it-the one with the methyl, which would give a singlet. Also, the methyl itself would be the other singlet since it is adjacent to the same carbon mentioned above.
I hope thats correct
Now i get it..
another Q.. If this was 13C NMR how many would that be? would it be 4 singlets?