Word problem and translation

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If Marvin gave two less than half his applis to Edna, he would have four more than twice the number of apples as Edna.what's the equation?

Ok Let Marvins aples be M

and Edna's be E

so Marvin gave (M/2) -2
This is equal to 2E + 4

so

(M/2) - 2 = 2E + 4

So, M - 4 = 4E + 8
M - 4E = 4 or if you want you can write it as M= 4E + 4
 
If Marvin gave two less than half his applis to Edna, he would have four more than twice the number of apples as Edna.what's the equation?
Let's say the number of apples = x

Edna's apples = x/2 - 2 (two less than half of his apples)
Now, when Marvin gives this many apples to Edna, he'll be left with:

x - [x/2 -2]

And this number is equal to four more than twice the number of apples as Edna's:

x - [x/2 -2] = (2[x/2 - 2]) + 4

CHECK:
4 - [4/2 - 2] = 2(4/2 - 2) + 4
4 - 0 = 0 + 4
4 = 4 (We're golden)

x/2 + 2 = x -4 + 4

x/2 + 2 = x

2 = x - x/2

1/2(x) = 2

x = 4
Plug it in to check your work!!
 
Let's say the number of apples = x

Edna's apples = x/2 - 2 (two less than half of his apples)
Now, when Marvin gives this many apples to Edna, he'll be left with:

x - [x/2 -2]

And this number is equal to four more than twice the number of apples as Edna's:

x - [x/2 -2] = (2[x/2 - 2]) + 4

x/2 + 2 = x -4 + 4

x/2 + 2 = x

2 = x - x/2

1/2(x) = 2

x = 4


x - [x/2 -2] = (2[x/2 - 2]) + 4....that's what i got when i solved the problem but the answer is x - [x/2 -2] =2 (E + [x/2 - 2]) + 4.
 
x - [x/2 -2] = (2[x/2 - 2]) + 4....that's what i got when i solved the problem but the answer is x - [x/2 -2] =2 (E + [x/2 - 2]) + 4.
Then I'm not sure.
Because, when I check with x = 4, it seems like we have the right answer.
Our answer can be written as:
x - [x/2 -2] = (2[x/2 - 2]) + 4
x - [x/2 -2] = ([x/2 - 2] + [x/2 - 2]) + 4
x - [x/2 -2] = (E + [x/2 - 2]) + 4
But I'm not sure where they're coming up with that 2.
 
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If Marvin gave two less than half his applis to Edna, he would have four more than twice the number of apples as Edna.what's the equation?
Marvin's = m
Edna's = e

m - (m/2 - 2) is what Marvin will be left with after giving his apples to Edna.
e + (m/2 - 2) is what Edna will have after Marvin gives her the apples.

Remember that what Marvin will have = 2(what edna will have) + 4

So

(m - (m/2 - 2)) = 2(e + (m/2 - 2)) + 4 is your equation.

m/2 + 2 = 2e + m
2 = 2e + m/2
2 - 2e = m/2
4 - 4e = m
So m = 4(1-e)

Can't really get much more simplified than that. Would need more information to do the rest.

So yes the solution e = 0 and m = 4 does work. There's really nothing else that works though (the only other integer that 'e' could be is 1 but then 'm' would be 0 and if you put that into the problem it won't make sense.
 
Let's say the number of apples = x

Edna's apples = x/2 - 2 (two less than half of his apples)
Now, when Marvin gives this many apples to Edna, he'll be left with:

x - [x/2 -2]

And this number is equal to four more than twice the number of apples as Edna's:

x - [x/2 -2] = (2[x/2 - 2]) + 4

CHECK:
4 - [4/2 - 2] = 2(4/2 - 2) + 4
4 - 0 = 0 + 4
4 = 4 (We're golden)

x/2 + 2 = x -4 + 4

x/2 + 2 = x

2 = x - x/2

1/2(x) = 2

x = 4
Plug it in to check your work!!

Oh yeah you seem right. I totally forgot to subtratct what marvin gave from what he had. 🙁 I hope I dont make retarted mistakes like these on the exam.
 
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