So I was reading Chads notes, and noticed something I wrote.
2C (S) + O2 (g) --> 2 CO2 + Heat
1 2
SO if we add something like Ar ( inert gas not part of the equation to the left pressure is increased. However, from example problems I think it had no effect on shifting the equilibrium. If we had a mole ration of 1:1 on both sides and then added an inert gas again not part of the equation would the change in pressure force the equation to go the opposite of the way it is added.
2C (S) + O2 (g) --> 2 CO2 + Heat
1 2
SO if we add something like Ar ( inert gas not part of the equation to the left pressure is increased. However, from example problems I think it had no effect on shifting the equilibrium. If we had a mole ration of 1:1 on both sides and then added an inert gas again not part of the equation would the change in pressure force the equation to go the opposite of the way it is added.