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how are you guys solving questions that involve ln ???
Is there any tricks to this?
Is there any tricks to this?
ln(x) = 2.3log(x)
Or close enough for the MCAT at least
I have a question as well...
how do you go from pka to Ka?
if pka = 6.4
then,
pka = -log Ka, and Ka= 10^-pka
but Ka is not 1 x 10^-6.4.
All I know is that if you had it's, __ x 10^-7.
But how do you estimate that number correctly?
my kaplan answer says 4.
wow...that is pretty complicated without a calc/computer and i cant tell you the answer. What i can tell you is technically Ka IS 1*10^-6.4 ...
because you can rewrite that as 1 / 10^6.4 ....and estimate that to be
____*10^-7 ...4 is probably the closest estimation but i cant tell you exactly how to get a definite one
well it is tough. but think about how you calculate pH from an H concentration. Let's say you had 6*10^-7 as you h concentration. you know the pH is between 6 and 7. let's say 6.4
now, do the same thing backwards: pH is 6.4 how do you get the H concentration? well it has to be between 1*10^-6 and 1*10^-7. you dont need anything more specific than that.
does the kaplan book give any reasoning on why it's 4 X 10^-7?
were all the choices ___*10^-7?
if that was the case....very unfair IMO.