-log(zx10^-y) = y-logz
do I have the expression down right?
I don't think so? Because log of 1x10^-3 ---> with the equation, comes out to be 3 - log (1) = 3
(not -3)
do I have the expression down right?
I don't think so? Because log of 1x10^-3 ---> with the equation, comes out to be 3 - log (1) = 3
(not -3)