- Joined
- Jan 3, 2012
- Messages
- 1,137
- Reaction score
- 398
At 0 degrees C a gas is dissolved in water at a mole fraction of 2x10^-18. What is the molality of this solution given the molecular weight of the gas is 32g/mole.
Mole fraction = moles solute/moles total. In his answer he sorta ignores the "moles total" part and just assumes it's 1 mol of water. I'm confused, since the total moles includes the moles of gas. Are we ignoring it because it's so small?
To find molality shouldn't it be moles gas/ mass of (total moles - moles gas)
Mole fraction = moles solute/moles total. In his answer he sorta ignores the "moles total" part and just assumes it's 1 mol of water. I'm confused, since the total moles includes the moles of gas. Are we ignoring it because it's so small?
To find molality shouldn't it be moles gas/ mass of (total moles - moles gas)