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I was looking over the thread "AAMC9 Q&A" but no one seems to have answered question #144 in BS.
The question reads:
If chromosomal duplication before tetrad formation occurred twice during spermatogenesis, while the other steps of meiosis proceeded normally, which of the following would result from a single spermatocyte?
a)one tetraploid sperm
b) four diploid sperm
c)four haploid sperm
d) eight haploid sperm
The answer is b.
I understand that if the cell goes through 2 duplications you will get double the amount of DNA as compared to a cell that only goes through one duplication and thus you'll get 4 haploid cells. I guess my real question is that during metaphase 1 instead of forming a tetrad, do you form an octatrad? (I made up that word.) And then that "octatrad" goes through normal meioisis and forms 4 diploid sperm? Hopefully that made sense. Thanks!
The question reads:
If chromosomal duplication before tetrad formation occurred twice during spermatogenesis, while the other steps of meiosis proceeded normally, which of the following would result from a single spermatocyte?
a)one tetraploid sperm
b) four diploid sperm
c)four haploid sperm
d) eight haploid sperm
The answer is b.
I understand that if the cell goes through 2 duplications you will get double the amount of DNA as compared to a cell that only goes through one duplication and thus you'll get 4 haploid cells. I guess my real question is that during metaphase 1 instead of forming a tetrad, do you form an octatrad? (I made up that word.) And then that "octatrad" goes through normal meioisis and forms 4 diploid sperm? Hopefully that made sense. Thanks!