achiever bio q

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Mstoothlady2012

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A gene locus of two alleles belonging to a population of 10,000 members is in a state of Hardy-Weinberg equilibrium. What is the frequency of heterozygotes if 9,898 individuals collectively exhibit dominant trait?

Since it says that 9898 people exhibit dominant trait, it means that all 9898 have atleast 1 dominant allele righ? So doesnt this mean p = 9898/10000 = 0.98 ?
 
Another question...

If three identical anticodons each being represented by the same code If three identical anticodons of GAU are found matching consecutively along an mRNA frame, what will be the corresponding base sequence on the original DNA stretch?

Isn't this basically asking which DNA strand was used to make GAUGAUGAU mRNA? Arrghh so irritating when I dont even understand the question.....
 
Another question...

If three identical anticodons each being represented by the same code If three identical anticodons of GAU are found matching consecutively along an mRNA frame, what will be the corresponding base sequence on the original DNA stretch?

Isn't this basically asking which DNA strand was used to make GAUGAUGAU mRNA? Arrghh so irritating when I dont even understand the question.....

You have tRNA anti-codon GAUGAUGAU, so your mRNA codons will have CUACUACUA, and your DNA will have GATGATGAT

DNA is complementary to mRNA which is complementary to the tRNA sequence, but dont forget that T's dont show up in RNA, uracil (U) replaces it instead
 
A gene locus of two alleles belonging to a population of 10,000 members is in a state of Hardy-Weinberg equilibrium. What is the frequency of heterozygotes if 9,898 individuals collectively exhibit dominant trait?

Since it says that 9898 people exhibit dominant trait, it means that all 9898 have atleast 1 dominant allele righ? So doesnt this mean p = 9898/10000 = 0.98 ?

For this one it says that 9,898 exhibit the dominant trait (basically saying phenotype) so the dominant phenotype is distinguished by PP (two alleles not just one). So the dominant frequency is 9,898/10,000 = .9898 = p^2

Find p=.995 so 1-.995 = .005 and this equals your recessive allele frequency...
So to find the heterozygote frequency you just multiply 2(p)(q) = 2(.995)(.005)= .01 = 1%

This makes sense because you have a HUGE percentage of the population exhibiting the dominant phenotype (trait) thereofore the recessive phenotype frequency will be very very small and the heterozygote frequency will be just as small
 
For this one it says that 9,898 exhibit the dominant trait (basically saying phenotype) so the dominant phenotype is distinguished by PP (two alleles not just one). So the dominant frequency is 9,898/10,000 = .9898 = p^2

Find p=.995 so 1-.995 = .005 and this equals your recessive allele frequency...
So to find the heterozygote frequency you just multiply 2(p)(q) = 2(.995)(.005)= .01 = 1%

This makes sense because you have a HUGE percentage of the population exhibiting the dominant phenotype (trait) thereofore the recessive phenotype frequency will be very very small and the heterozygote frequency will be just as small

wow i thought i did this correctly but i just took a look at their answer and explanation...its freaking weird...they do a lot of rounding but the idea is pretty much the same...I did mine on calculator and got exact numbers but they round it somewhere which is weird...
 
but I thought dominant trait means either PP or Pp. Doesn't trait represent phenotype and not genotype?
 
You have tRNA anti-codon GAUGAUGAU, so your mRNA codons will have CUACUACUA, and your DNA will have GATGATGAT

DNA is complementary to mRNA which is complementary to the tRNA sequence, but dont forget that T's dont show up in RNA, uracil (U) replaces it instead
ahh!! anticodons **keyword**...didnt' read the question properly. I was thinking mRNA...drove me crazy lol thanks!
 
but I thought dominant trait means either PP or Pp. Doesn't trait represent phenotype and not genotype?

ya trait is phenotype, a dominant phenotype can either be PP or Pp...thats why this question is weird as hell, when i first read it i noticed the same thing you did...i think they messed up on this...tried to trick ppl but they tricked themselves
 
NVM it finally just clicked in my head, SINCE they tell you the dominant trait is 9,898 out of the 10,000 population then you know the recessive trait (can only be pp) is 10000-9898=q2, then you take the q and find p from it and your set...
 
NVM it finally just clicked in my head, SINCE they tell you the dominant trait is 9,898 out of the 10,000 population then you know the recessive trait (can only be pp) is 10000-9898=q2, then you take the q and find p from it and your set...
yea their solution makes sense to me. But I was just thinking what was wrong with my explanation. yea what you said makes sense dominant trait could be PP or Pp so you can't really figure out p or p^2 value. Thanks! Have you already done achiever tests? how did you do on the 2nd one. Did you look at my horrible scores?
 
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