Achiever Q

[Ruthless]

Help me out if you can.





Which statement CORRECTLY explains the following acid-base reaction at equilibrium?
CH3H2C:- + HOC(CH3)3 .<->. CH3CH3 + -:Ö:C(CH3)3


a. Weaker acid, HOC(CH3)3, and weaker base, CH3H2C:-, will be present in abundance
b. Stronger acid, HOC(CH3)3, and stronger base, CH3H2C:-, will be present in abundance
c. Weaker acid, CH3CH3, and stronger base, -:Ö:C(CH3)3, will be present in abundance
d. Stronger acid, CH3CH3, and weaker base, -:Ö:C(CH3)3, will be present in abundance
e. Weaker acid, CH3CH3, and weaker base, -:Ö:C(CH3)3, will be present in abundance.


This is Q71 in achiever3. Anyone by any chance can help me out with a good explanation as to why the answer is e.

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[NumbaOneStunna]

In Acid/Base Rxn's at equilibrium the weaker acid and base will be present in larger quantities. Looking at all four molecules, it should be obvious that the alcohol (-OH) is more acidic than CH3-CH3.

As a rule the stronger the acid is the weaker it's conjugate base is. Since the alcohol is more acidic than CH3-CH3 it's conjugate base (-:Ö:C(CH3)3 ) is weaker than the conjugate base of CH3-CH3 (CH3-CH2)

 

[Ruthless]

thanks bro, thats wat i needed