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ok thank you also one more question...can you explain a little about how aromaticity and acidity and basicity are connected? I don't understand how something would be more acidic just because when you deprotonate it results in an aromatic ion.
Consider acetic acid, pKa= 4.34. when pH = 2 which is present?
a) Acetate Ion
b) Protonated acid
c) Neutral Ion
d) Zwitterion
e) None of these
Firstly, I think they meant Neutral Acid for answer choice C.
Secondly, I'm going to assume that there are only molecules of acetate and acetic acid present in the solution.
Use the HendersonHasselbalch equation and you'll see that in order for the solution's pH to be 2, there must be more molecules of acid than base.
pH = pKa + log (acetate ion / acetic acid)
ok thank you also one more question...can you explain a little about how aromaticity and acidity and basicity are connected? I don't understand how something would be more acidic just because when you deprotonate it results in an aromatic ion.
Are you asking how substituents affect acidity/basicity or how aromaticity affects acidity/basicity
how aromaticity affects acidity/ basicity
Ok, lets look at the classic example of pyrollidine and its aromatic cousin, pyrrole.
The basicity of amines are determined by how available the lone pairs are to serve as a lewis base. If the electrons are 'tied' to some sort of system, they're not as available. Pyrole is not very basic at all, its pKa is around 17-20. It's not basic because the lone pair of nitrogen is tied to the 6 pi aromatic system. Pyrollidine, on the other hand, has a freely available pair of electrons. It is very basic.
edit: avaible = available ...I'm too lazy to fix it lol
wow thank you so much, the pictures deff helped with my understanding I really appreciate it!! So how do you know if the lone pair is tied to a system? if there are other double bonds within the ring?