Algebra Question

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T+m2*((2T-mg)/m)=mg
Tm+m2*(2T-mg)=m^2g
Tm+m2*2T-m2*mg=m^2g
T(m+2m2)=m^2g+m2*mg
T=(m^2g+m2*mg)/(m+2m2)
 
T+m2*((2T-mg)/m)=mg
Tm+m2*(2T-mg)=m^2g
Tm+m2*2T-m2*mg=m^2g
T(m+2m2)=m^2g+m2*mg
T=(m^2g+m2*mg)/(m+2m2)

That's what I got too, but the answer is T = (3/5)mg.

I think the "m2" is supposed to be 2m? I saw how simplified the answer was and gave up.
 
That's what I got too, but the answer is T = (3/5)mg.

I think the "m2" is supposed to be 2m? I saw how simplified the answer was and gave up.

That works - if m2=2m (that's m sub 2 equals twice m), just plugging in my final result will give you 0.6mg. 🙂
 
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