Amino acids
- Thread starter Awuah29
- Start date
Awuah29 said:
This is definitely not something that will be on the DAT. I think that if the PH of the environment is much lower than the PI, then anything that can be protonated will be protonated. If the PH of the environment is higher than the PI, anything that can be unprotonated, will be. These are the extreme cases and the PH (relative to the PI) will determine the degree of charge. At least I think this is right. It's been a while since I've seen this in class. 😳
- Joined
- Oct 24, 2005
- Messages
- 57
- Reaction score
- 0
- Points
- 0
tinman831 said:
I didn't get this question , but it might be on the dat,
basically if your PI is below the pH, you are looking or a negative charge, if the pI is above the pH, you get a positive charge....ummm okay same as what tinman said 🙂 but another way to look at it 😛
It is really simple!
You know the amino side will lose/gain charge at a pH of around 9 and the caroxy side will lose/gain charge at around pH of 2.
Knowing that, if the pH is 4 for example, you know that it's above the IP (isoelectric point) for the carboxy side (meaning it's less acidic then the isoelectric point) so the proton will be lost from the carboxy side. On the amino end, the pH of 4 is below (more acidic) then the isoelectric point so that side will remain protinated.
Now look at all your charges, you have a - from the deprotinated carboxy side and a + from the protinated amino side. So overall neutral.
Now look if the pH is raised to 11. Now the carboxy will still be deprotinated and have a - charge, and the amino side is now below the pH so it will also be deprotinated and will be neutral. Now you have an overall charge of -. You have to do the same for the other side groups that could have a charge.
Good luck
You know the amino side will lose/gain charge at a pH of around 9 and the caroxy side will lose/gain charge at around pH of 2.
Knowing that, if the pH is 4 for example, you know that it's above the IP (isoelectric point) for the carboxy side (meaning it's less acidic then the isoelectric point) so the proton will be lost from the carboxy side. On the amino end, the pH of 4 is below (more acidic) then the isoelectric point so that side will remain protinated.
Now look at all your charges, you have a - from the deprotinated carboxy side and a + from the protinated amino side. So overall neutral.
Now look if the pH is raised to 11. Now the carboxy will still be deprotinated and have a - charge, and the amino side is now below the pH so it will also be deprotinated and will be neutral. Now you have an overall charge of -. You have to do the same for the other side groups that could have a charge.
Good luck
