angular momentum quantum number

[adrakdavra]

---

Members do not see this ad.

What is the value for the angular momentum quantum number, for the orbital from which a Na atom loses 1 electron to form Na +?​

​

 

[Doctor246853]

What is the value for the angular momentum quantum number, for the orbital from which a Na atom loses 1 electron to form Na +?​

Well, the angular momemtum quantum number is basically describing the orbital, so.... s=0, p=1, d=2, f=3. So when Na loses an eletron it has the same electron config as Ne which is in the p orbital. The "l" corresponding to the p orbital is 1. In short the answer is 1.

 

[rjosh33]

Well, the angular momemtum quantum number is basically describing the orbital, so.... s=0, p=1, d=2, f=3. So when Na loses an eletron it has the same electron config as Ne which is in the p orbital. The "l" corresponding to the p orbital is 1. In short the answer is 1.

Isn't the question asking for the angular quantum number for which orbital loses the electron? So since it's lost from a 3s orbital, the angular quantum number should be 0, for s.

 

[MangoPlant]

The valence electron for Na is 3s^1 (n = 3, l = 0) so the angular quantum number (l) is 0

 

[Doctor246853]

The valence electron for Na is 3s^1 (n = 3, l = 0) so the angular quantum number (l) is 0

I stand corrected.

 

[adrakdavra]

I know the answer is zero but why is it that when Na losses an electron from the 3s it does not go to the 2p and make L=1 a possible answer.