# another probability question

#### anteater85

10+ Year Member
Five hours after sasha began walking from A to B, a distance of 100 miles, Mario started walking along the same road from B to A. If Sasha's walking rate was 2 miles per hour and Mario's was 3 miles per hour, how many miles had Mario walked when they met?

#### razblo

10+ Year Member
I don't think this is a probability question, but anyways...

Combine the two rates.

2mph + 3mph = 5mph

Divide the total distance by the combined rate.

(100miles)/(5miles/hour) = 20 hours [miles cancel]

Multiply that 20 hours by the 3mph (Mario's speed).

20 hours x 3miles/hour = 60 miles [hours cancel]

#### cheerio3

10+ Year Member
It should be 18 hours * 3 mph, because Sasha had already walked 5 hours at 2 mph (covered 10 miles) and 100 total miles minus 10 miles = 90 miles. 90 miles/5 mph= 18 hours and Mario would walk 3 mph per 18 hours.

#### razblo

10+ Year Member
It should be 18 hours * 3 mph, because Sasha had already walked 5 hours at 2 mph (covered 10 miles) and 100 total miles minus 10 miles = 90 miles. 90 miles/5 mph= 18 hours and Mario would walk 3 mph per 18 hours.
Pfff, details

#### Streetwolf

##### Ultra Senior Member
10+ Year Member
7+ Year Member
Nevermind read the question wrong haha.

Ignore my last post.

I saw that Mario walked from A to B when he actually walked B to A.